Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A car goes on a horizontal circular road of radius R =
meter, the speed increasing at a constant rate
= a = 1 m/s 2 , starting from rest. The friction coefficient between the road and the tyre is µ= 0.2 Find the time at which the car will skid.
Text Solution
Verified by ExpertsThe correct answer is:
A
Given:
- Radius of the circular road, R
- Acceleration, a = 1 m/s2
- Coefficient of friction, µ = 0.2
- Initial speed, u = 0 (starting from rest)
Step 1: Calculate the maximum speed before skidding using the formula:
v_{max} = µ * g * R, where g is the acceleration due to gravity (approx. 9.81 m/s2).
Substituting the values:
v_{max} = 0.2 * 9.81 * R
v_{max} = 1.962 * R
Step 2: Use the equation of motion to find the time taken to reach this speed.
v = u + a * t
Therefore, t = (v_{max} - u) / a = (1.962 * R - 0) / 1 = 1.962 * R.
Thus: The time at which the car will skid is t = 1.962 * R seconds.
- Radius of the circular road, R
- Acceleration, a = 1 m/s2
- Coefficient of friction, µ = 0.2
- Initial speed, u = 0 (starting from rest)
Step 1: Calculate the maximum speed before skidding using the formula:
v_{max} = µ * g * R, where g is the acceleration due to gravity (approx. 9.81 m/s2).
Substituting the values:
v_{max} = 0.2 * 9.81 * R
v_{max} = 1.962 * R
Step 2: Use the equation of motion to find the time taken to reach this speed.
v = u + a * t
Therefore, t = (v_{max} - u) / a = (1.962 * R - 0) / 1 = 1.962 * R.
Thus: The time at which the car will skid is t = 1.962 * R seconds.
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